Optimal. Leaf size=89 \[ -\frac {5 b^2 \sqrt {a+b x^2}}{16 x^2}-\frac {5 b \left (a+b x^2\right )^{3/2}}{24 x^4}-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}-\frac {5 b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 \sqrt {a}} \]
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Rubi [A]
time = 0.04, antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {272, 43, 65,
214} \begin {gather*} -\frac {5 b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 \sqrt {a}}-\frac {5 b^2 \sqrt {a+b x^2}}{16 x^2}-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}-\frac {5 b \left (a+b x^2\right )^{3/2}}{24 x^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 65
Rule 214
Rule 272
Rubi steps
\begin {align*} \int \frac {\left (a+b x^2\right )^{5/2}}{x^7} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {(a+b x)^{5/2}}{x^4} \, dx,x,x^2\right )\\ &=-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}+\frac {1}{12} (5 b) \text {Subst}\left (\int \frac {(a+b x)^{3/2}}{x^3} \, dx,x,x^2\right )\\ &=-\frac {5 b \left (a+b x^2\right )^{3/2}}{24 x^4}-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}+\frac {1}{16} \left (5 b^2\right ) \text {Subst}\left (\int \frac {\sqrt {a+b x}}{x^2} \, dx,x,x^2\right )\\ &=-\frac {5 b^2 \sqrt {a+b x^2}}{16 x^2}-\frac {5 b \left (a+b x^2\right )^{3/2}}{24 x^4}-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}+\frac {1}{32} \left (5 b^3\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^2\right )\\ &=-\frac {5 b^2 \sqrt {a+b x^2}}{16 x^2}-\frac {5 b \left (a+b x^2\right )^{3/2}}{24 x^4}-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}+\frac {1}{16} \left (5 b^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^2}\right )\\ &=-\frac {5 b^2 \sqrt {a+b x^2}}{16 x^2}-\frac {5 b \left (a+b x^2\right )^{3/2}}{24 x^4}-\frac {\left (a+b x^2\right )^{5/2}}{6 x^6}-\frac {5 b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 \sqrt {a}}\\ \end {align*}
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Mathematica [A]
time = 0.12, size = 70, normalized size = 0.79 \begin {gather*} \frac {\sqrt {a+b x^2} \left (-8 a^2-26 a b x^2-33 b^2 x^4\right )}{48 x^6}-\frac {5 b^3 \tanh ^{-1}\left (\frac {\sqrt {a+b x^2}}{\sqrt {a}}\right )}{16 \sqrt {a}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.06, size = 139, normalized size = 1.56
method | result | size |
risch | \(-\frac {\sqrt {b \,x^{2}+a}\, \left (33 b^{2} x^{4}+26 a b \,x^{2}+8 a^{2}\right )}{48 x^{6}}-\frac {5 b^{3} \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )}{16 \sqrt {a}}\) | \(68\) |
default | \(-\frac {\left (b \,x^{2}+a \right )^{\frac {7}{2}}}{6 a \,x^{6}}+\frac {b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {7}{2}}}{4 a \,x^{4}}+\frac {3 b \left (-\frac {\left (b \,x^{2}+a \right )^{\frac {7}{2}}}{2 a \,x^{2}}+\frac {5 b \left (\frac {\left (b \,x^{2}+a \right )^{\frac {5}{2}}}{5}+a \left (\frac {\left (b \,x^{2}+a \right )^{\frac {3}{2}}}{3}+a \left (\sqrt {b \,x^{2}+a}-\sqrt {a}\, \ln \left (\frac {2 a +2 \sqrt {a}\, \sqrt {b \,x^{2}+a}}{x}\right )\right )\right )\right )}{2 a}\right )}{4 a}\right )}{6 a}\) | \(139\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 127, normalized size = 1.43 \begin {gather*} -\frac {5 \, b^{3} \operatorname {arsinh}\left (\frac {a}{\sqrt {a b} {\left | x \right |}}\right )}{16 \, \sqrt {a}} + \frac {{\left (b x^{2} + a\right )}^{\frac {5}{2}} b^{3}}{16 \, a^{3}} + \frac {5 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} b^{3}}{48 \, a^{2}} + \frac {5 \, \sqrt {b x^{2} + a} b^{3}}{16 \, a} - \frac {{\left (b x^{2} + a\right )}^{\frac {7}{2}} b^{2}}{16 \, a^{3} x^{2}} - \frac {{\left (b x^{2} + a\right )}^{\frac {7}{2}} b}{24 \, a^{2} x^{4}} - \frac {{\left (b x^{2} + a\right )}^{\frac {7}{2}}}{6 \, a x^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.27, size = 158, normalized size = 1.78 \begin {gather*} \left [\frac {15 \, \sqrt {a} b^{3} x^{6} \log \left (-\frac {b x^{2} - 2 \, \sqrt {b x^{2} + a} \sqrt {a} + 2 \, a}{x^{2}}\right ) - 2 \, {\left (33 \, a b^{2} x^{4} + 26 \, a^{2} b x^{2} + 8 \, a^{3}\right )} \sqrt {b x^{2} + a}}{96 \, a x^{6}}, \frac {15 \, \sqrt {-a} b^{3} x^{6} \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x^{2} + a}}\right ) - {\left (33 \, a b^{2} x^{4} + 26 \, a^{2} b x^{2} + 8 \, a^{3}\right )} \sqrt {b x^{2} + a}}{48 \, a x^{6}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 2.84, size = 99, normalized size = 1.11 \begin {gather*} - \frac {a^{2} \sqrt {b} \sqrt {\frac {a}{b x^{2}} + 1}}{6 x^{5}} - \frac {13 a b^{\frac {3}{2}} \sqrt {\frac {a}{b x^{2}} + 1}}{24 x^{3}} - \frac {11 b^{\frac {5}{2}} \sqrt {\frac {a}{b x^{2}} + 1}}{16 x} - \frac {5 b^{3} \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x} \right )}}{16 \sqrt {a}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.63, size = 87, normalized size = 0.98 \begin {gather*} \frac {\frac {15 \, b^{4} \arctan \left (\frac {\sqrt {b x^{2} + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} - \frac {33 \, {\left (b x^{2} + a\right )}^{\frac {5}{2}} b^{4} - 40 \, {\left (b x^{2} + a\right )}^{\frac {3}{2}} a b^{4} + 15 \, \sqrt {b x^{2} + a} a^{2} b^{4}}{b^{3} x^{6}}}{48 \, b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 5.20, size = 72, normalized size = 0.81 \begin {gather*} \frac {5\,a\,{\left (b\,x^2+a\right )}^{3/2}}{6\,x^6}-\frac {11\,{\left (b\,x^2+a\right )}^{5/2}}{16\,x^6}-\frac {5\,a^2\,\sqrt {b\,x^2+a}}{16\,x^6}+\frac {b^3\,\mathrm {atan}\left (\frac {\sqrt {b\,x^2+a}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,5{}\mathrm {i}}{16\,\sqrt {a}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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